tj2001cobra
Wednesday, October 24, 2012 10:34:54 PM
OK, my sister called me and asked me a question for her son's math class. I figured out the answer, but I dont have an equation or "mathematical explanation" for it.

What is the largest number possible that isn't some combination of 4 and 7?

The answer is 17 (I'm fairly certain of this) but I can't write an equation for it. This is 5th grade math, so it shouldn't be that hard... but I haven't done math in 20+ years.

So, can someone give me an equation or other mathematical explanation?

Thanks.

z6joker9
Wednesday, October 24, 2012 11:14:25 PM
I don't understand the question.
SMGBobbyScott
Wednesday, October 24, 2012 11:19:27 PM
It is a Log problem
tj2001cobra
Wednesday, October 24, 2012 11:25:40 PM

I don't understand the question.

z6joker9 wrote:

I'm not sure how to ask the question differently. The way it was posed to the students was something like "if you have 4 packs of nuggets and 7 packs of nuggets, what is the largest number that some combination of 4 and 7 dont divide into."

So, if you picked 33, you would say that 3 4-packs and 3 7-packs make 33.

Basically, what is the largest number that some multiple of 7 and 4 dont add up to.

rfenst
Wednesday, October 24, 2012 11:41:45 PM
So, are you looking for another CBid math war? If so, Why not ask Jimmy? LMFAO.

Actually, I would ask JTokash.

If the question is clear, he will calculate the answer and then lay it all out for you in such a simple, clear fashion that you will understand both how any formula is derived and how he determined the answer.

(Justin, if you see this, know that you and Liz are still in my mind. Hope life is sweet and wonderful for both of you!)

z6joker9
Thursday, October 25, 2012 12:41:52 AM
I had something typed but cbid didn't like it (Error Message: There is something wrong in your post) and now it's gone. I'll give you the basics.

Frobenius (coin) problem

Formula when you're only dealing with 2 numbers

(x-1)(y-1)-1

or

xy-x-y

So yes, 17 is the correct answer. You can google the why if you want more info, it's time for bed.

There is an alternate formula for dealing with 3 different numbers. No known formula for 4 or more IIRC.

tj2001cobra
Thursday, October 25, 2012 1:00:19 AM

I had something typed but cbid didn't like it (There is something wrong in your post) and now it's gone. I'll give you the basics.

Frobenius (coin) problem

Formula when you're only dealing with 2 numbers

(x-1)(y-1)-1

or

xy-x-y

So yes, 17 is the correct answer. You can google the why if you want more info, it's time for bed.

There is an alternate formula for dealing with 3 different numbers. No known formula for 4 or more IIRC.

z6joker9 wrote:

I didn't change either of my posts, so I'm not sure what was wrong with them, but your formulas appear to be correct. Thank you. I passed them on to my sister and her husband so they could pass it on to their son.

I love this place.

z6joker9
Thursday, October 25, 2012 8:25:57 AM
Sorry I meant that "There is something wrong in your post" was the error message cbid gave me when I tried to post my first, much longer reply, which then disappeared. I'm guessing some of the math was mistaken for code and cbid wouldn't allow it.
cacman
Thursday, October 25, 2012 10:25:20 AM
Professor Terguson: ...Say it!... Say it!... Say it!

Thornton Melon: The answer is... [the answer hits him] ... 4?

t33bone
Thursday, October 25, 2012 2:06:09 PM
😕 😕 😕 😕
DrMaddVibe
Thursday, October 25, 2012 2:41:33 PM
You fellas in the 'Sip...put yer socks back on. You're not foolin' anyone with that fancy cipherin'![whip]
Stinkdyr
Thursday, October 25, 2012 3:23:50 PM
You might have the question wrong....

and in that case, the answer is 42!

So long, and thanks for all the fish!!

🍺