if you think of a cigar as a cylinder, its volume "filler" will be pi*r^2*L pi=3.14.... r=radius l=length.
the surface area "wrapper" of this cylinder is 2*pi*r*L
so as the radius "ring gauge" increases, the amount of filler gets squared. which reduces the wrapper to filler ratio... and vice versa for smaller ring gauges
outtatime wrote: